[最も選択された] 2^x 2^y=2^x y find dy/dx at x=y=1 838059
Solved Dy Sec Y 11 12 Du 1 4v2 Dx 1 X2 Dx 3v 13 X X X Dy Dt 14 Dx 3x 1 Y2 3 2 15 Y 1 Dy Yecos For the differential equation, find the particular solution (x – y2x) dx – (y x2y) dy = 0 when x = 2, y = 0 Mathematics and Statistics Advertisement Remove all ads Advertisement Remove all adsDy/dx=(x^2y^21)/2xy Hi, This is a Homogeneous differential equation So put y=vx and solve, ie keeping v as avariable find dv/dx in terms of dy/dx and substi 2^x 2^y=2^x y find dy/dx at x=y=1